Parallelogram

Parallelogram
Parallelogram.svg
This parallelogram is a rhomboid as its angles are oblique.
Type Quadrilateral
Edges and vertices 4
Symmetry group C2 (2)

In geometry, a parallelogram is a quadrilateral with two pairs of parallel sides. In Euclidean Geometry, the opposite or facing sides of a parallelogram are of equal length and the opposite angles of a parallelogram are of equal measure. The congruence of opposite sides and opposite angles is a direct consequence of the Euclidean Parallel Postulate and neither condition can be proven without appealing to the Euclidean Parallel Postulate or one of its equivalent formulations. The three-dimensional counterpart of a parallelogram is a parallelepiped.

The etymology (in Greek παραλληλ-όγραμμον, a shape "of parallel lines") reflects the definition.

Contents

Properties

Types of parallelogram

Proof that diagonals bisect each other

Parallelogram ABCD

To prove that the diagonals of a parallelogram bisect each other, we will use congruent triangles:

\angle ABE \cong \angle CDE (alternate interior angles are equal in measure)
\angle BAE \cong \angle DCE (alternate interior angles are equal in measure).

(since these are angles that a transversal makes with parallel lines AB and DC ).

Also, side AB is equal in length to side DC, since opposite sides of a parallelogram are equal in length.

Therefore triangles ABE and CDE are congruent (ASA postulate, two corresponding angles and the included side).

Therefore,

AE = CE
BE = DE.

Since the diagonals AC and BD divide each other into segments of equal length, the diagonals bisect each other.

Separately, since the diagonals AC and BD  bisect each other at point E, point E  is the midpoint of each diagonal.

The area formula

Area of the parallelogram is in blue

The area formula,

A = B \times H,\,

can be derived as follows:

The area of the parallelogram to the right (the blue area) is the total area of the rectangle less the area of the two orange triangles. The area of the rectangle is

A_\text{rect} = (B+A) \times H\,

and the area of a single orange triangle is

A_\text{tri} = \frac{1}{2} A \times H\, or S_\text{tri} = \frac{1}{2} bh.

Therefore, the area of the parallelogram is

A =
A_\text{rect} - 2 \times A_\text{tri} =
\left( (B+A) \times H \right) - \left( A \times H \right) =
B \times H.\,

Computing the area of a parallelogram

Let a,b\in\R^2 and let V=[a\ b]\in\R^{2\times2} denote the matrix with columns a and b. Then the area of the parallelogram generated by a and b is equal to |\det(V)|

Let a,b\in\R^n and let V=[a\ b]\in\R^{n\times2} Then the area of the parallelogram generated by a and b is equal to \sqrt{\det(V^T V)}

Let a,b,c\in\R^2. Then the area of the parallelogram with vertices at a, b and c is equivalent to the absolute value of the determinant of a matrix built using a, b and c as rows with the last column padded using ones as follows:

 V = \left| \det \begin{bmatrix}
        a_1 & a_2 & 1 \\
        b_1 & b_2 & 1 \\
        c_1 & c_2 & 1
 \end{bmatrix} \right|.

See also

External links